(1/7)^2x=1/49

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Solution for (1/7)^2x=1/49 equation: 



(1/7)^2x=1/49

We move all terms to the left:

(1/7)^2x-(1/49)=0



Domain of the equation: 7)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/7)^2x-(+1/49)=0

We get rid of parentheses

(+1/7)^2x-1/49=0

We calculate fractions


()/7^2x*49)+(-7x)/7^2x*49)=0

We calculate fractions

We do not support expression: x^6

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